Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Bond length$\propto \frac{1}{\mathrm{b}\mathrm{o}\mathrm{n}\mathrm{d}\text{ order}}$

Bond length$=\frac{\text{no. of bonding }\bar{\mathrm{e}}-\text{no. of antibonding }\stackrel{\mathrm{̄}}{\text{e}}}{2}$

Bond orders of${\mathrm{O}}_2^{+}\text{, }{\mathrm{O}}_2^{-}\text{, }{\mathrm{O}}_2^{2-}\text{ and }{\mathrm{O}}_2^{2+}\mathrm{ }$are respectively 2.5, 1.5, 1 and 3

Hence${\mathrm{O}}_2^{2+}$is shortest in bond length as have max .bond order.