Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mathrm{C}}_2=\left(12\right);$ $\mathrm{\sigma }1{\mathrm{s}}^2<\stackrel{\mathrm{*}}{\mathrm{\sigma }}1{\mathrm{s}}^2<\mathrm{\sigma }2{\mathrm{s}}^2<\stackrel{\mathrm{*}}{\mathrm{\sigma }}2{\mathrm{s}}^2<\mathrm{\pi }2{\mathrm{p}}_{\mathrm{x}}^2=\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}^2$

So according to MOT, the orbitals involved in bonding are only pie orbital.

Hence ${\mathrm{C}}_2$ contains only $\mathrm{\pi }$ bonds.