Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(a) ${\mathrm{N}}_2(14):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\star }2s^2\pi 2p_x^2=\pi 2p_y{}^2$ $\sigma 2p_z^2$ B.O. $=\frac{1}{2}\left(N_b-N_a\right)=\frac{1}{2}(10-4)=3.0$ ${\mathrm{CN}}^{-}(14):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^2=\pi 2p_y^2$ $\sigma 2p_z^2$ B.O. $=\frac{1}{2}(10-4)=3.0$ (b) ${\mathrm{O}}_2^{+}(15):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2=$ $\pi 2p_y^2{\pi }^{\star }2p_x^1$ B.O. $=\frac{1}{2}(10-5)=2.5$ $\mathrm{NO}(15):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\star }2s^2\sigma 2p_z^2$ $\pi 2p_x^2=\pi 2p_y^2{\pi }^{\star }2p_x^1$ B.O. $=\frac{1}{2}(10-5)=2.5$ (c) ${\mathrm{F}}_2^{-}(19):\sigma 1s^2{\sigma }^{\star }1s^2\sigma 2s^2{\sigma }^{\star }2s^2\sigma 2p_z^2\pi 2p_x^2=$ $\pi 2p_y^2{\pi }^{\star }2p_x^2={\pi }^{\ast }2p_y^2{\sigma }^{\ast }2p_z^1$ B.O. $=\frac{1}{2}(10-9)=0.5$ ${\mathrm{O}}_2^{2-}(18):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2=$ $\pi 2p_y^2{\pi }^{\star }2p_x^2={\pi }^{\star }2p_y^2$ B.O. $=\frac{1}{2}(10-8)=1.0$ (d) ${\mathrm{B}}_2^{2-}(12):\sigma 1s^2{\sigma }^{\star }1s^2\sigma 2s^2{\sigma }^{\star }2s^2\pi 2p_x^2=\pi 2p_y^2$ B.O. $=\frac{1}{2}(8-4)=2.0$ ${\mathrm{CN}}^{+}(12):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^2=\pi 2p_y^2$ B.O. $=\frac{1}{2}(8-4)=2.0$