Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMOTMedium2 minPYQ_2018

ChemistryMediumsingle choice

In the molecular orbital diagram for the molecular ion, $N_{2}^{+}$ , the number of electrons in the $σ_{2 p}$ molecular orbital is :

Options:

Answer:

Solution:

Total electrons in $N_{2}^{+} = (7 \times 2) - 1 = 13$ $N_{2}^{+} \to σ_{1 s^{2}}, σ_{1 s^{2}}^{*}, σ_{2 s^{2}}, σ_{2 s^{2}}^{*}, [π_{2 p_{x}}^{2} = π_{2 p_{y}}^{2}] σ_{2 p_{z}}^{1}$ Number of electron in $σ_{2 p_{z}}$ is $1$ .

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT

⏱ 2mℹ️ Source: PYQ_2018

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