Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(a) Polarising power of cations increases with the increasing charge. $\begin{array}{rl}& (+1)(+2)(+3)\\ & \mathrm{NaCl}<{\mathrm{MgCl}}_2<{\mathrm{AlCl}}_3\\ & \end{array}$ (b) Bond order $\propto \frac{1}{\text{ Bond length }}$ Bond order $=\frac{\text{ Bond order of each }\mathrm{C}-\mathrm{O}\text{ bond }}{\text{ Total no. of resonating structures }}$
Hence, the decreasing order of bond length is ${\mathrm{CO}}_3^{2-}>{\mathrm{HCO}}_2^{-}>{\mathrm{CO}}_2>\mathrm{CO}$. (c) $\mathrm{Cl}⟵\mathrm{Be}\rightleftarrows \mathrm{Cl}$,
Correct order of dipole moment : ${\mathrm{BeCl}}_2<{\mathrm{NF}}_3<{\mathrm{NH}}_3$ (d) Correct order of bond angle : $\begin{array}{rl}& {\mathrm{BF}}_3>{\mathrm{SiH}}_4>{\mathrm{NH}}_3>{\mathrm{H}}_2\mathrm{S}\\ & \\ & \begin{array}{llll}120^{\circ }& 109^{\circ }28^{\prime }& 107^{\circ }& 93.3^{\circ }\end{array}\\ & \\ & \end{array}$