Chemistry - CHEMICAL BONDING Question with Solution | TestHub

electronegativity of $\mathrm{F}$ is greater than that of $\mathrm{O}$

${\mathrm{H}}_2\mathrm{O}$ involves $\mathrm{H}$-bonding, whereas ${\mathrm{BeF}}_2$ is a discrete molecule

${\mathrm{H}}_2\mathrm{O}$ is angular and ${\mathrm{BeF}}_2$ is linear

${\mathrm{H}}_2\mathrm{O}$ is linear and ${\mathrm{BeF}}_2$ is angular.