Chemistry - CHEMICAL BONDING Question with Solution | TestHub

I. Number of electrons in $\stackrel{+}{\mathrm{C}}{\mathrm{H}}_3=6+3-1=8$

II. Number of electrons in ${\mathrm{NH}}_2^{-}=7+2+1=10$

III. Number of electrons in ${\mathrm{NH}}_4^{+}=7+4-1=10$

IV. Number of electrons in ${\mathrm{NH}}_3=7+3=10$

Since, species with same number of electrons are called isoelectronic species, Hence, $\mathrm{IInd},\mathrm{IIIrd}$ and $\mathrm{IVth}$ are isoelectronic.