Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Both $\mathrm{CO}$ and ${\mathrm{NO}}^{+}$have 14 electrons. The electronic configuration is $\sigma 1s^2$ ${\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p^{2}z\pi 2p_z^2=\pi 2p_y^2$ Bond order $=\frac{10-4}{2}=3$