Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Higher the lattice enthalpy lower will be solubilityi.e., lattice enthalpy $\propto \frac{1}{\text{ Solubility }}$ Since the lattice enthalpy of alkali metals follow the order $\mathrm{Li}>\mathrm{Na}>\mathrm{K}>\mathrm{Rb}$ Hence the correct order of solubility is $\mathrm{LiF}<\mathrm{NaF}<\mathrm{KF}<\mathrm{RbF}$