Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The molecular orbital configurations of $$\begin{array}{l}{\mathrm{O}}_2^{+},{\mathrm{O}}_2^{-},{\mathrm{O}}_2^{2-}\text{ and }{\mathrm{O}}_2\text{ are }\\ {\mathrm{O}}_2^{+}=\sigma 1s^2,\sigma 1s^2,\sigma 2s^2,\sigma 2s^2,\sigma 2p_z^2,\pi 2p_x^2\\ \approx \pi 2p_y^2,\pi 2p_x^1\approx \pi 2p_y^{\ast }\\ {\mathrm{O}}_2^{-}=\sigma 1s^2,\sigma 1s^2,\sigma 2s^2,\sigma 2s^2,\sigma 2p_z^2,\pi 2p_x^2\\ \approx \pi 2p_y^2,\pi 2p_x^{\ast }\approx \pi 2p_y^1\\ {\mathrm{O}}_2^{2-}=\sigma 1s^2,\sigma 1s^2,\sigma 2s^2,\sigma 2s^2,\sigma 2p_z^2,\pi 2p_x^2\\ \approx \pi 2p_y^2,\pi 2p_x^{\ast }\approx \pi 2p_y^2\end{array}$$ $$\begin{array}{l}{\mathrm{O}}_2=\sigma 1s^2,\sigma 1s^2,\sigma 2s^2,\sigma 2s^2,\sigma 2p_z^2,\pi 2p_x^2\\ \approx \pi 2p_y^2,\pi 2p_x^1\approx \pi 2p_y^1\end{array}$$ and the electronic configuration of $\mathrm{O}$ and ${\mathrm{O}}^{+}$are $$\begin{array}{l}\mathrm{O}=1s^2,2s^2,2p_x^2,2p_y^1,2p_z^1\\ {\mathrm{O}}^{+}=1s^2,2s^2,2p_x^1,2p_y^1,2p_z^1\end{array}$$ As ${\mathrm{O}}_2^{+},{\mathrm{O}}_2,{\mathrm{O}}_2^{-},\mathrm{O}$ and ${\mathrm{O}}^{+}$have unpaired electrons, hence are paramagnetic.