Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Higher the bond order higher will be the stability. When the bond order of two molecules are same, the molecule with least number of antibonding electrons is more stable. Molecular orbital configuration of ${\mathrm{H}}_2^{+}$is ${\mathrm{H}}_2^{+}(1)=\sigma 1{\mathrm{s}}^1$ $$\mathrm{BO}=\frac{1-0}{2}=0.5$$ Molecular orbital configuration of ${\mathrm{He}}_2^{+}$is $$\begin{array}{l}{\mathrm{He}}_2^{+}(3)=\sigma 1{\mathrm{s}}^2,\stackrel{\ast }{\sigma }{\mathrm{s}}^1\\ \mathrm{BO}=\frac{2-1}{2}=0.5\end{array}$$ Hence, stability of ${\mathrm{H}}_2^{+}>$stability of ${\mathrm{He}}_2^{+}$.