Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$$\begin{array}{ll}{\mathrm{NO}}_2^{-}& \to s{p}^2\\ {\mathrm{NO}}_3^{-}& \to s{p}^2\\ {\mathrm{NH}}_2^{+}& \to s{p}^3\end{array}$$ $$\begin{array}{ll}{\mathrm{NH}}_4^{-}& \to s{p}^3\\ {\mathrm{SCN}}^{-}& \to sp\end{array}$$ $\therefore {\mathrm{NO}}_2^{-}$and ${\mathrm{NO}}_3^{-}$both have the same hybridisation.
$\therefore {\left[\mathrm{Co}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{2+}$ has minimum number of unpaired electrons and thus, minimum paramagnetic behaviour.