Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Bond order of ${\mathrm{N}}_2=3$, bond order of ${\mathrm{O}}_2=2$. Higher the bond order, higher is the bond dissociation energy i.e. higher stability or less reactivity. Thus ${\mathrm{N}}_2$ is less reactive than ${\mathrm{O}}_2$. Higher the bond order, shorter is the bond length. Higher bond order of ${\mathrm{N}}_2$ shows its shorter bond length.