Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$\mathrm{CO}$ : total $e^{-s}=6+8=14$ $$\begin{array}{c}\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\pi 2p_x^{1+1}=\pi 2p_y^{1+1},\sigma 2p_z^2\\ \mathrm{BO}=\frac{10-4}{2}=3\\ {\mathrm{NO}}^{-}=\text{Total }{e}^{-}s=7+8+1=16\\ \sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\sigma 2p_z^2,\pi 2p_x^{1+1}\\ =\pi 2p_y^{1+1},{\pi }^{\ast }2p_x^1={\pi }^{\ast }2p_y^1\\ \mathrm{BO}=\frac{10-6}{2}=\frac{4}{2}=2\end{array}$$ Total number of $e^{-}s:{\mathrm{CN}}^{-}=6+7+1=14$ $${\mathrm{N}}_2=7+7=14$$