Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Hybridisation $=\frac{1}{2}$ [Number of valence electrons of central atom $+$ no. of monovalent atoms attached to it $+$ negative charge if any $-$ positive charge if any] $\begin{array}{l}=\frac{1}{2}[6+4+0-0]=5={\mathrm{sp}}^3\mathrm{d}\\ \left[\because \mathrm{Te}(52)=[\mathrm{Kr}]4{\mathrm{d}}^{10}5{\mathrm{s}}^{2}5{\mathrm{p}}^4\right]\end{array}$