Chemistry - CHEMICAL BONDING Question with Solution | TestHub

In ${\mathrm{ClF}}_3$, the chlorine atom is $s{p}^{3}d$ hybridised. So, the bonds are not equal and have trigonal-bipyramidal geometry.
${\mathrm{BF}}_3$ and ${\mathrm{AlF}}_3$ show a trigonal symmetric structure because of $s{p}^2$ hybridisation.
${\mathrm{NF}}_3$ shows pyramidal geometry because of $s{p}^3$ hybridisation.