Assertion : All F − S − F angle in SF 4 is greater than 9 0 ∘ but less than 18 0 ∘ . Reason : The lone pair-bond pair repulsion is weaker than bond pair-bond pair repulsion.

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Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyMedium2 minPYQ_2004

ChemistryMediumsingle choice

Assertion : All $F - S - F$ angle in $SF_{4}$ is greater than $9 0^{\circ}$ but less than $18 0^{\circ}$ . Reason : The lone pair-bond pair repulsion is weaker than bond pair-bond pair repulsion.

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Answer:

Solution:

Due to greater lone pair - bond pair repulsions than bond pair - bond pair repulsions, the $F - S - F$ bond angle decreases from $18 0^{\circ}$ .

Stream:AIIMSSubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy

⏱ 2mℹ️ Source: PYQ_2004

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