Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Carbon, oxygen and nitrogen atoms do not have any $d$-orbital available. Therefore, in ${\mathrm{CO}}_3^{2-},{\mathrm{NO}}_2^{-}$ and ${\mathrm{NO}}_3^{-}$, there is no possibility of $p\pi -d\pi$ type of bonding. In ${\mathrm{PO}}_4{}^{3-}$ phosphorus atom has vacant $d$-orbital available which is used to form $p\pi -d\pi$ type of bonding with $p$-orbital of oxygen atom.