Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

Oxidation of 1 -naphthylamine with acidified ${\mathrm{KMnO}}_4$ is easier than that of 1-nitronaphthalene.

Oxidation of 1 -nitro naphthalene with ${\mathrm{KMnO}}_4/{\mathrm{H}}^{+}$gives phthalic acid.

Oxidation of 1-naphthylamine with ${\mathrm{KMnO}}_4/{\mathrm{H}}^{+}$gives phthalic acid.

Cyclo-octatetraene decolourizes ${\mathrm{Br}}_2$ in ${\mathrm{CCl}}_4$ readily.