Assume that the reaction of MeMgBr with ethylacetate proceeds with $100%$ conversion to give tert-butanol. The volume of 0.2 M solution of MeMgBr required to convert 10 mL of a 0.025 M solution of ethyl acetate to tert-butanol is $____$ mL.
(Round off to one decimal place)

Question

Assume that the reaction of MeMgBr with ethylacetate proceeds with $100%$ conversion to give tert-butanol. The volume of 0.2 M solution of MeMgBr required to convert 10 mL of a 0.025 M solution of ethyl acetate to tert-butanol is $____$ mL.

(Round off to one decimal place)

TestHub · Accepted Answer

1 mol of ethyl acetate reacts with 2 mol of MeMgBr. Millimoles of ethyl acetate = $10 \times 0.025 = 0.25$ millimoles. So, for complete reaction, MeMgBr must be 0.50 millimoles.

The volume of 0.2 M MeMgBr containing 0.50 millimoles would be:

$0.2 \times V = 0.5$

$V = \frac{0.5}{0.2}$

$V = 2.5 m L$

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