Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

${\mathrm{Br}}_2/{\mathrm{AlBr}}_3,{\mathrm{HNO}}_3/{\mathrm{H}}_2{\mathrm{SO}}_4,\mathrm{Mg}/$ether,${\mathrm{CO}}_2,{\mathrm{H}}_3{\mathrm{O}}^{+}$

${\mathrm{Br}}_2/{\mathrm{AlBr}}_3,\mathrm{NaCN},{\mathrm{H}}_3{\mathrm{O}}^{+},{\mathrm{HNO}}_3/{\mathrm{H}}_2{\mathrm{SO}}_4$

${\mathrm{Br}}_2/{\mathrm{AlBr}}_3,{\mathrm{HNO}}_3/{\mathrm{H}}_2{\mathrm{SO}}_4,\mathrm{NaCN},{\mathrm{H}}_3{\mathrm{O}}^{+}$

${\mathrm{HNO}}_3/{\mathrm{H}}_2{\mathrm{SO}}_4,{\mathrm{Br}}_2/{\mathrm{AlBr}}_3,\mathrm{Mg}/$ether,${\mathrm{CO}}_2,{\mathrm{H}}_3{\mathrm{O}}^{+}$