CHCl 3 + MeCOMe → OH − A → excess KOH B → NaOH − CaO C → KOBr D

Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

ChemistryCarboxylic acid and their DerivativesHydrolysis of Acid derivative & other reactionEasy2 minPYQ_2020

ChemistryEasysingle choice

${CHCl}_{3} + MeCOMe \overset{{OH}^{-}}{\to} A \overset{excess KOH}{\to} B \overset{NaOH - CaO}{\to} C \overset{KOBr}{\to} D$

Answer:

Solution:

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Carboxylic acid and their DerivativesSubtopic:Hydrolysis of Acid derivative & other reaction

⏱ 2mℹ️ Source: PYQ_2020

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