Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

In phenyl benzoatethe$1^{\mathrm{st}}$ring gets deactivated, while$2^{\mathrm{nd}}$ring gets activated due to lone pairs on oxygen atom. So it can give ortho or para bromo product. But the ortho position is sterically hindered, so it will give para compound as a major product.