C | | O − NH 2 → P 2 O 5 A → (i)CH 3 MgBr ii H 3 O + B → i I 2 + Ca ( OH ) 2 ii H 2 O C ; Product is

C | | O - N H 2 → P 2 O 5 C ≡ N → i C H 3 M g B r i i H 3 O + C | | O - C H 3 → i I 2 + Ca OH 2 ii H 2 O C | | O - O H

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Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

ChemistryCarboxylic acid and their DerivativesMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

$\overset{O}{\overset{| |}{C}} - {NH}_{2} \overset{P_{2} O_{5}}{\to} A \overset{{(i)CH}_{3} MgBr (ii) H_{3} O^{+}}{\to} B \overset{(i) I_{2} + Ca {(OH)}_{2} (ii) H_{2} O}{\to} C;$ Product is

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Answer:

Solution:

$\overset{O}{\overset{| |}{C}} - N H_{2} \overset{P_{2} O_{5}}{\to}$ $C \equiv N$ $\overset{(i) C H_{3} M g B r (i i) H_{3} O^{+}}{\to}$ $\overset{O}{\overset{| |}{C}} - {C H}_{3}$ $\overset{(i) I_{2} + Ca {(OH)}_{2} (ii) H_{2} O}{\to}$ $\overset{O}{\overset{| |}{C}} - O H$

Stream:NTA_ABHYASSubject:ChemistryTopic:Carboxylic acid and their DerivativesSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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