In the given reaction sequence C 6 H 5 − COOH → SOCl 2 ( A ) → NH 2 OH ( B ) → NaOH / Δ ( C ) , 'C' will be

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Here the final product C is aniline and the reaction is as follows
$C_{6} H_{5} - C O O H \overset{S O C l_{2}}{\to} \underset{(A)}{C_{6} H_{5} - \overset{O}{\overset{| |}{C}} - C l} \overset{N H_{2} O H}{\to} \underset{(B)}{C_{6} H_{5} - \overset{O}{\overset{| |}{C}} - N H O H} \overset{N a O H}{\to} [C_{6} H_{5} - N = C = O] \to C_{6} H_{5} - N H_{2}$

Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

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