Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

An optically active compound$\mathrm{‘}\mathrm{X}\mathrm{’}$has molecular formula${\mathrm{C}}_4{\mathrm{H}}_8{\mathrm{O}}_3$. It evolves$\mathrm{C}{\mathrm{O}}_2$with$\mathrm{N}\mathrm{a}\mathrm{H}\mathrm{C}{\mathrm{O}}_3.$$\mathrm{‘}\mathrm{X}\mathrm{’}$reacts with$\mathrm{L}\mathrm{i}\mathrm{A}\mathrm{l}{\mathrm{H}}_4$to give an achiral compound$\mathrm{‘}\mathrm{X}\mathrm{’}$is–