Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

${\mathrm{Br}}_2/{\mathrm{FeBr}}_3,{\mathrm{KMnO}}_4,{\mathrm{HNO}}_3/{\mathrm{H}}_2{\mathrm{SO}}_4$

${\mathrm{KMnO}}_4,{\mathrm{Br}}_2/{\mathrm{FeBr}}_3,{\mathrm{HNO}}_3$

${\mathrm{HNO}}_3,{\mathrm{Br}}_2/{\mathrm{FeBr}}_3,{\mathrm{KMnO}}_4$

${\mathrm{HNO}}_3,{\mathrm{KMnO}}_4,{\mathrm{Br}}_2/{\mathrm{FeBr}}_3$