Chemistry - Carbonyl compounds Question with Solution | TestHub

The given reaction is a Beckmann Rearrangement, where a ketone is converted into an oxime using NH₂OH and then rearranged in an acidic medium (H⁺). During the rearrangement, the alkyl or aryl group positioned anti to the leaving -OH group migrates from the carbon atom to the nitrogen atom. Due to steric reasons, the oxime isomer with the ethyl (Et) group situated anti to the -OH group undergoes major migration. The migration of the ethyl group followed by tautomerization yields the amide Ph-C(=O)-NH-Et. Thus, the correct major product A is Option (A).