Chemistry - Carbonyl compounds Question with Solution | TestHub
ChemistryCarbonyl compoundsAldol condensation and Cannizzarro reactionMedium2 minQB
ChemistryMediumsingle choice
The reaction of 50% aq. KOH on an equimolar mixture of 4-methylbenzaldehyde and formaldehyde followed by acidification gives :
Options:
Answer:
B
Solution:
4-Methylbenzaldehyde has no alpha hydrogen, so with strong base it undergoes the Cannizzaro reaction. In this crossed Cannizzaro reaction formaldehyde is the better reducing agent: it is oxidised to formate (HCOOH after acidification), and the aromatic aldehyde is reduced to 4-methylbenzyl alcohol.
Products: 4-methylbenzyl alcohol + HCOOH, option (B).
Stream:JEESubject:ChemistryTopic:Carbonyl compoundsSubtopic:Aldol condensation and Cannizzarro reaction
⏱ 2mℹ️ Source: QB
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