How many different aldehydes with molecular formula C 5 H 10 O will form two oximes on reaction with H₂N–OH?

Question

How many different aldehydes with molecular formula C 5 ​ H 10 ​ O will form two oximes on reaction with H₂N–OH?

TestHub · Accepted Answer

Pentanal, 2-methylbutanal, 3-methylbutanal and 2,2-dimethylpropanal are the four constitutional aldehydes. Each RCH=NOH has distinct H/R on carbon and gives syn/anti oximes. Total four; optical aldehyde forms are not counted separately.

Source solution: n-butyl–CHO, sec-butyl–CHO, isobutyl–CHO, tert-butyl–CHO.

Chemistry - Carbonyl compounds Question with Solution | TestHub

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