Consider the following reaction Propanal + Methanal = → ( ii ) Δ ( iii ) NaCN ( iv ) H 3 O + ( i ) dil . NaOH P roduct B ( C 5 H 8 O 3 ) The correct statement for product B is. It is

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Propanal and methanal undergo aldol condensation reaction with sodium hydroxide. The $α, β$ -unsaturated compound undergo $1, 4 -$ conjugated addition with cyanide ion gives a racemic mixture. The cyanide undergo acidic hydrolysis gives carboxylic acid.

Carboxylic acid will give ${CO}_{2}$ gas, with ${NaHCO}_{3}$ solution

Chemistry - Carbonyl compounds Question with Solution | TestHub

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