Chemistry - Carbonyl compounds Question with Solution | TestHub

Electronic configuration of$\mathrm{C}{\mathrm{u}}^{2+}$is$4{\mathrm{s}}^0$$3{\mathrm{d}}^9$, during complex formation one electron from$3\mathrm{d}$gets excited to$4\mathrm{s}$. Hence the hybridization of$\mathrm{C}\mathrm{u}$is$\mathrm{d}\mathrm{s}{\mathrm{p}}^2$, square planar.