Chemistry - Carbonyl compounds Question with Solution | TestHub

As more the number of ion more is conductivity so here$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_6]\mathrm{C}{\mathrm{l}}_3$shows maximum conductivity as it has four ions.
$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_6]\mathrm{C}{\mathrm{l}}_3$$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_6{]}^{3+}+3\mathrm{C}{\mathrm{l}}^{-}$
$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_5\mathrm{C}\mathrm{l}]\mathrm{C}{\mathrm{l}}_2$$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_5\mathrm{C}\mathrm{l}{]}^{2+}+2\mathrm{C}{\mathrm{l}}^{-}$
$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_4\mathrm{C}{\mathrm{l}}_2]\mathrm{C}\mathrm{l}$$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_4\mathrm{C}{\mathrm{l}}_2{]}^{+}+\mathrm{C}{\mathrm{l}}^{-}$
$\left[\mathrm{C}\mathrm{r}\right(\mathrm{N}{\mathrm{H}}_3{)}_3\mathrm{C}{\mathrm{l}}_3]$Does not ionize