Chemistry - Carbonyl compounds Question with Solution | TestHub

$\mathrm{F}{\mathrm{e}}^{3+}=\left(\mathrm{A}\mathrm{r}\right)3{\mathrm{d}}^5$
$\mathrm{C}{\mathrm{o}}^{2+}=\left(\mathrm{A}\mathrm{r}\right)3{\mathrm{d}}^7$
Hence,$\mathrm{F}{\mathrm{e}}^{3+}$has 5 unpaired electrons and$\mathrm{C}{\mathrm{o}}^{2+}$has 3 unpaired electrons
${\mathrm{\mu }}_{\mathrm{F}{\mathrm{e}}^{3+}}=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{5\times 7}=\sqrt{35}$
${\mathrm{\mu }}_{\mathrm{C}{\mathrm{o}}^{3+}}=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{3\times 5}=\sqrt{15}$