Chemistry - Carbonyl compounds Question with Solution | TestHub

In$\left[{\text{Mn}}_{\text{2}}{\text{(CO)}}_{\text{10}}\right]$, there is one$\text{Mn}-\text{Mn}$bond
Electron present in 2 Mn = 50
Electrons donated by 10 CO = 20
Electrons in one$\text{Mn}-\text{Mn}$bond = 2
Total electrons = 72
So EAN per$\mathrm{M}\mathrm{n}=\frac{72}{2}=36$.