Equilibrium constant for two complexes are
$A :$ $K_{4} [F e (C N)_{6}]$ $2.6 \times 1 0^{37}$ (for dissociation)
$B : K_{3} [F e (C N)_{6}]$ $1.9 \times 1 0^{17}$ (for dissociation)

Question

Equilibrium constant for two complexes are A : K 4 [ F e ( C N ) 6 ] 2.6 × 1 0 37 (for dissociation) B : K 3 [ F e ( C N ) 6 ] 1.9 × 1 0 17 (for dissociation)

TestHub · Accepted Answer

Here K 3 [ F e ( C N ) 6 ] with dissociation constant 1.9 × 1 0 17 is more stable than K 4 [ F e ( C N ) 6 ] with dissociation constant 2.6 × 1 0 37 Higher is the dissociation constant lesser will be the stability of complex.

Chemistry - Carbonyl compounds Question with Solution | TestHub

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