Arrange the following in order of decreasing number of unpaired electrons:
I: ${[F e (H_{2} O_{6})]}^{2 +}$
II: ${[F e {(C N)}_{6}]}^{3 -}$
III: ${[F e {(C N)}_{6}]}^{4 -}$
IV: ${[F e {(H_{2} O)}_{6}]}^{3 +}$

Question

Arrange the following in order of decreasing number of unpaired electrons: I: F e H 2 O 6 2 + II: F e C N 6 3 – III: F e C N 6 4 – IV: F e H 2 O 6 3 +

TestHub · Accepted Answer

F e H 2 O 6 2 + – n o o f u n p a i r e d e – – 4 , F e H 2 O 6 3 + - n o o f u n p a i r e d e – – 5 F e C N 6 3 – – n o o f u n p a i r e d e – – 1 F e C N 6 4 – – n o o f u n p a i r e d e – – 0

Chemistry - Carbonyl compounds Question with Solution | TestHub

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