Among the following ions, which one has the highest paramagnetism?

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TestHub · Accepted Answer

Water is a weak-field ligand, so the crystal field splitting paired in lower energy. Hence, electrons are not paired in lower energy d-orbitals (i.e., no pairing of electrons in d-orbitals occurs aganist the Hunds rule).

Species	Oxidation state of central metal ion	Configuration of central metal ion	Number of unpaired d-electrons
A. $[C r (H_{2} O)_{6}]^{3 +}$	+3	$C r^{3 +} (3 d^{3})$	3
B. ${[Fe {(H_{2} O)}_{6}]}^{2 +}$	+2	$F e^{2 +} (3 d^{6})$	4
C. $[C u (H_{2} O)_{6}]^{2 +}$	+2	$C u^{2 +} (3 d^{9})$	1
D. $[Z n (H_{2} O)_{6}]^{2 +}$	+2	$Z n^{2 +} (3 d^{10})$	0

The more the number of unpaired electrons, the higher is the paramagnetic character of the metal ion, As a result, $[F e (H_{2} O)_{6}]^{2 +}$ has the highest paramagnetism.

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