Chemistry - Carbonyl compounds Question with Solution | TestHub

Since '$\mathrm{A}$' gives positive silver mirror test therefore, it must be an aldehyde or $\mathrm{\alpha }$ -Hydroxyketone.

Reaction with semicarbazide indicates that $\mathrm{A}$ can be an aldehyde or ketone.

Reaction with ${\mathrm{OH}}^{-}$ i.e., aldol condensation (by assuming alkali to be dilute) indicates that $\mathrm{A}$ is aldehyde as aldol reaction of ketones is reversible and carried out in special apparatus.

These indicate option $\left(\mathrm{iii}\right)$.

​​​​​​​