Chemistry - Carbonyl compounds Question with Solution | TestHub

${\mathrm{CH}}_3\mathrm{CHO}$ and ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{CHO}$ both being aliphatic aldehydes react with Tollen's reagent, Fehling solution and Benedict solution. So, these reagents cannot be used to distinguish them. ${\mathrm{CH}}_3\mathrm{CHO}$ reacts with $\mathrm{NaOH}$ and ${\mathrm{I}}_2$ to give yellow crystals of iodoform while ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{CHO}$ does not react with it. $\begin{array}{rl}{\mathrm{CH}}_3\mathrm{CHO}+3{\mathrm{I}}_2+& 4\mathrm{NaOH}⟶{\mathrm{CHI}}_3+\mathrm{HCOONa}+3\mathrm{NaI}+3{\mathrm{H}}_2\mathrm{O}\\ {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{CHO}+{\mathrm{I}}_2& +\mathrm{NaOH}⟶\text{No reaction }\end{array}$ Thus, ${\mathrm{CH}}_3\mathrm{CHO}$ and ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{CHO}$ can be distinguished by iodoform test.