Chemistry - Carbonyl compounds Question with Solution | TestHub

Let the volume of each acid $=V$ $pH$ of first, second and third acids $=3,4$ and 5 respectively $\left[H^{+}\right]$of first acid $\left(M_1\right)=1\times 10^{-3}\left[\therefore H^{+}=1\times 10^{-pH}\right]$ $\left[H^{+}\right]$of second acid $\left(M_2\right)=1\times 10^{-4}$ $\left[H^{+}\right]$of third acid $\left(M_3\right)=1\times 10^{-5}$ Total $\left[H^{+}\right]$concentrated of mixture $\begin{array}{rl}& (M)=\frac{M_1{V}_1+M_2{V}_2+M_3{V}_3}{V_1+V_2+V_3}\\ & =\frac{1\times 10^3\times V+1\times 10^4\times V+1\times 10^5\times V}{V+V+V}\\ & =\frac{1\times 10^3\times V(1+0.1+0.01)}{3V}\\ & =\frac{1.11\times 10^3}{3}=3.7\times 10^{-4}M\end{array}$