Chemistry - Polymer Question with Solution | TestHub

ChemistryPolymerMiscellaneous/MixedMedium2 minQB
ChemistryMediuminteger

The number of co-polymer(s) in the below list is/are X : (Nylon-6,6, Buna-N, Dacron, Buna-S, Teflon, PHBV) The number of carbohydrate (s) which show mutarotation in the below list is/are Y:

-D-Glucopyranose and -D-Glucopyranose , Lactose

-D-Fructofuranose and -D-Fructofuranose , Sucrose , maltose

The value of ?

Answer:
1
Solution:

Question Explanation: to identify number of copolymers and carbohydrates which show mutarotation. Concept: This question is based on copolymers and mutarotation. Solution : A copolymer is made from two (or more) different monomers. In the given polymer list: * Nylon-6,6 is made from hexamethylenediamine + adipic acid, making it a copolymer. * Buna-N (NBR) - butadiene + acrylonitrile → copolymer. * Dacron (PET) - ethylene glycol + terephthalic acid → copolymer. * Buna-S (SBR) - styrene + butadiene → copolymer. * Teflon (PTFE) - Polymer of tetrafluoroethylene (a single monomer) → homopolymer. * PHBV (poly(3-hydroxybutyrate-co-3-hydroxyvalerate)) → copolymer.

So .

Except for sucrose, all given carbohydrates can exhibit mutarotation because they possess a hemiacetal or hemiketal linkage:

* -D-Glucopyranose and -D-Glucopyranose → The bond at C-1 (anomeric carbon) is a hemiacetal linkage → mutarotation.

* -D-Fructofuranose and -D-Fructofuranose → At the anomeric carbon (C-2 in fructose), there is a hemiketal linkage (often grouped under hemiacetal linkages) → mutarotation. * Lactose → has one free hemiacetal linkage → mutarotation.

* Sucrose → Both anomeric carbons are involved in the glycosidic bond → no free hemiacetal → does not show mutarotation.

* In maltose, the second glucose unit still has a free anomeric carbon (C1) in hemiacetal form → mutarotation.

Thus.

 

 

 

Stream:JEESubject:ChemistryTopic:PolymerSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: QB

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