Chemistry - Biomolecules Question with Solution | TestHub
Match the column :
List - I | List - II |
|---|---|
(A) Sucrose | (P) Two acetal linkage
|
(B) Maltose | (Q) No hemiacetal linkage
|
(C) Lactose | (R) -1,4'-glycosidic bond |
(D) Cellulose | (S) One of the hydrolysis product is glucose |
Options:
Answer:
Solution:
Question Explanation:
Match the given saccharides with their structural characteristics.
Concept:
This question is based on structure and properties of disaccharides/polysaccharides.
Solution:
A (Sucrose): α − C1 (Glucose) → β − C2 (Fructose) linkage
Sucrose has an acetal (C1) and a ketal (C2) linkage → Two acetal linkage (P).
Sucrose is non-reducing sugar because absence of hemiacetal linkage .
A→P, Q, S.
B (Maltose): α − C1 (Glucose) → C4 (Glucose) linkage
Maltose on hydrolysis gives 2 moles of glucose
B → S
C (Lactose): β − C1 (Galactose) → C4 (Glucose) linkage
→ β − 1, 4′-glycosidic bond.
→ Lactose on hydrolysis gives glucose and galactose.
C → R, S
D (Cellulose): β − C1 (Glucose) → C4 (Glucose) linkage
Cellulose have β − 1, 4′-glycosidic linkage.
D → R
Mapping: A → P, Q, S.B → S.C → R, S.D → R,S.