Chemistry - Biomolecules Question with Solution | TestHub

$\left|z_1\right|+\left|z_2\right|+\left|z_3\right|=5$

At $\mathrm{pH}=2\stackrel{1}{N}{\mathrm{H}}_2$ and $\stackrel{2}{N}{\mathrm{H}}_2$ of Tyrosine and Lysine is + ve charged $(+1$ each $)$

$$+2\left|z_1\right|=2$$

At $\mathrm{pH}=6{\mathrm{NH}}_2$ of Lysine ( +1 ),

$$\mathrm{COOH}(-1)\text{ of glutamic acid, so because of dipolar ion exist }\left|{\mathrm{z}}_2\right|=0$$

At $\mathrm{pH}=11\mathrm{COOH}$ of Glutamic acid (-1)

COOH of Lysine (-1)

OH of phenol ( -1 )

$\left|{\mathrm{z}}_3\right|=3$