Chemistry - Biomolecules Question with Solution | TestHub

ChemistryBiomoleculesAMINO ACIDMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

DNA has 2500 total bases. Adenine makes up 32% of them. One strand yields 1250 mRNA bases.

The first 1248 mRNA bases form 416 full codons. Two terminal bases remain untranslated. Ignore start and stop codons in this calculation.

How many cytosine bases are present in the entire DNA segment?

Answer:

450.00

Solution:

Adenine $(A) = 32%$ Thymine ( T ) must be equal to A (Chargaff's rule) $\to T = 32%$ $A + T = 32% + 32% = 64%$ Remaining bases $= G + C = 100% - 64% = 36%$ Guanine $(G) =$ Cytosine $(C)$ (Chargaff's rule) $\to G = C = 36%/2 = 18%$ Number of cytosine bases $= 18%$ of 2500 $= (18/100) \times 2500$ $= 0.18 \times 2500$ $= 450.00$

Stream:JEESubject:ChemistryTopic:BiomoleculesSubtopic:AMINO ACID

⏱ 2mℹ️ Source: QB

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