The Δ H ∘ for the mutarotation of glucose in aqueous solution, α − D − glucose ( aq ) → β − D − glucose ( aq ) has been measured in a microcalorimeter and found to be 1.16 kJ . mol − 1 . The enthalpie

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The Δ H ∘ for the mutarotation of glucose in aqueous solution, α − D − glucose ( aq ) → β − D − glucose ( aq ) has been measured in a microcalorimeter and found to be 1.16 kJ . mol − 1 . The enthalpies of solution of the two forms of glucose have been determined to be α − D -glucose ( s ) → α − D -glucose ( aq ) Δ H ∘ = 10.72 kJ ⋅ mol − 1 β − D -glucose ( s ) → β − D -glucose ( aq ) Δ H ∘ = 4.68 kJ ⋅ mol − 1 Calculate Δ H ∘ (in kJ/mol ) for the mutarotation of solid α − D -glucose to solid β − D -glucose.

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Explain Question: To find calculate Δ H ∘ (in kJ / mol ) for the mutarotation of solid α − D -glucose to solid β - D - glucose. Concept: Enthalpy of solution. solution: (i) α − D − glucose (aq) → β − D − glucose (aq) Δ H ∘ = − 1.16 kJ mol − 1 (ii) α − D − glucose (s) → α − D − glucose (aq) Δ H ∘ = 10.72 kJ mol − 1 (iii) β − D − glucose (s) ⟶ β − D − glucose (aq) Δ H ∘ = 4.68 kJ . mol − 1 To obtain reaction (iv) α -D-glucose (s) → β -D-glucose (s) (iv) = (ii) + (i) - (iii) Δ H ∘ = 10.72 kJ mol − 1 + ( − 1.16 kJ mol − 1 ) − 4.68 kJ mol − 1 Δ H ∘ = 10.72 − 1.16 − 4.68 = 4.88 kJ mol − 1 Final Answer: (A)

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