Compound A , C 5 H 10 O 5 , given a tetraacetate with AC 2 O and oxidation of A with Br 2 - H 2 O gives an acid, C 5 H 10 O 6 . Reduction of A with HI gives isopentane. The possible structure of A is

Question

Compound A , C 5 H 10 O 5 , given a tetraacetate with AC 2 O and oxidation of A with Br 2 - H 2 O gives an acid, C 5 H 10 O 6 . Reduction of A with HI gives isopentane. The possible structure of A is :

TestHub · Accepted Answer

Formation of tetraacetate with acetic anhydride means compound A has four - OH linkage. Reduction of A with HI gives isopentane i.e. molecule contains five carbon atoms. So, C is the correct option

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