1f:["$","div",null,{"className":"px-6 pb-6","children":[false,["$","div",null,{"className":"text-foreground leading-relaxed mb-6","children":["$","div",null,{"className":"question-html prose dark:prose-invert max-w-none","dangerouslySetInnerHTML":{"__html":"

The ${pK}_{a}$ values of ionisable groups in lysine are $2.18,8.95$ and $10.79$ respectively. Find isoelectric point of lysine.

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$Isoelectric point = \frac{8.95 + 10.79}{2} = 9.87$

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Chemistry - Biomolecules Question with Solution | TestHub

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