Chemistry - Biomolecules Question with Solution | TestHub

$\underset{\begin{array}{c}\left[\alpha \right]=+112°\\ \left(36\%\right)\end{array}}{\mathrm{\alpha }-\mathrm{D}-\mathrm{G}\mathrm{l}\mathrm{u}\mathrm{c}\mathrm{o}\mathrm{s}\mathrm{e}}\rightleftharpoons \underset{\begin{array}{c}\left[\alpha \right]D=+52°\\ \left(0.02\%\right)\end{array}}{\mathrm{E}\mathrm{q}\mathrm{u}\mathrm{i}\mathrm{l}\mathrm{i}\mathrm{b}\mathrm{r}\mathrm{i}\mathrm{u}\mathrm{m}\mathrm{m}\mathrm{i}\mathrm{x}\mathrm{t}\mathrm{u}\mathrm{r}\mathrm{e}}\rightleftharpoons \underset{\begin{array}{c}\left[\alpha \right]D=+19°\\ \left(64\%\right)\end{array}}{\mathrm{\beta }-\mathrm{D}-\mathrm{G}\mathrm{l}\mathrm{u}\mathrm{c}\mathrm{o}\mathrm{s}\mathrm{e}}$
Glucose has two forms$\mathrm{\alpha }$and$\mathrm{\beta }$. When either of these two is dissolved in water and allowed to stand, it gets converted to an equilibrium mixture of$\mathrm{\alpha }$and$\mathrm{\beta }$forms.