Match each species and orbit in Column I with the statements in Column II that are true for the electron ( v 1 of H = 2.18 × 1 0 6 m/s , r 1 of H = 0.529 Å, E 1 of H = − 13.6 eV) (a Column I ent

Question

Match each species and orbit in Column I with the statements in Column II that are true for the electron ( $v_{1}$ of $H = 2.18 \times 1 0^{6} m/s, r_{1}$ of $H = 0.529$ Å, $E_{1}$ of $H = - 13.6$ eV) (a Column I entry may match more than one Column II entry):

Column I (Species, orbit)	Column II (Statement)
(P) $He^{+}, n = 3$	(1) speed = $2.18 \times 1 0^{6}$ m/s
(Q) $Li^{2 +}, n = 2$	(2) speed = $3.27 \times 1 0^{6}$ m/s
(R) $Be^{3 +}, n = 4$	(3) speed = $1.45 \times 1 0^{6}$ m/s
(S) H, $n = 1$	(4) radius greater than 2 Å
	(5) radius less than 1 Å
	(6) kinetic energy = 13.6 eV

Choose the option with the correct matching:

TestHub · Accepted Answer

v = 2.18 × 1 0 6 Z / n , r = 0.529 n 2 / Z Å, KE = 13.6 Z 2 / n 2 eV. (P) Z / n = 2/3 : v = 1.45 × 1 0 6 ( 3 ) ; r = 0.529 × 9/2 = 2.38 Å (4); KE = 6.04 eV. (Q) Z / n = 3/2 : v = 3.27 × 1 0 6 ( 2 ) ; r = 0.529 × 4/3 = 0.705 Å (5); KE = 30.6 eV. (R) Z / n = 1 : v = 2.18 × 1 0 6 ( 1 ) ; r = 0.529 × 16/4 = 2.12 Å (4); KE = 13.6 eV (6). (S) v = 2.18 × 1 0 6 ( 1 ) ; r = 0.529 Å (5); KE = 13.6 eV (6). Correct matching: P to 3,4; Q to 2,5; R to 1,4,6; S to 1,5,6. Answer: (C).

Chemistry - Atomic Structure Question with Solution | TestHub

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